餘數的 的英文怎麼說
中文拼音 [yúshǔde]
餘數的
英文
odd-
They represent 38. 1 % of the total species that have been identified. we performed preliminary study on those mycofiora of agarics under those forests. based on our study, we identified one tropical element family : entolomataceae, two north temperate element families : hygrophoraceae and cortinariaceae ; the other 11 families all belong to cosmopolitan element
根據論文所研究的傘菌類群,從科的地理分佈看,熱帶亞熱帶成分只有粉褶菌科entolomataceae一科;北溫帶成分的科有兩個,即蠟傘科hygrophoraceae和絲膜菌科;其餘的科均為世界廣布的科,占總科數的78 . 6 。After like near future arrowroot continent dam flies a shop sign afresh go situation and to the limit of one ' s capacity rises should notice early days goes situation, if be pulled considerably, magnify again quantity, be about vigilance is banker shipment ( this time may be a few longer, banker is sucked prepare time to grow more, shipment time is long ), island visitting extensive region goes situation ( be about in first time to the limit of one ' s capacity first shipment ) if early days is to pass dish of full share, ( at present the individual thinks to have treasure new the sources of energy ) in the to the limit of one ' s capacity when breaking through strong line or resistance line but follow - up, that ability is really true the quantity adds valence to rise dropping is not must to the limit of one ' s capacity, and shrink the volume drops consequence is more serious, because early days banker already gave money, basically be, use odd amount to be bungled again dish, medicinal powder door meet disastrous
如近期葛洲壩重新開牌后的走勢而放量上升要注重前期走勢,假如大幅拉升后再放大量,就要警惕是莊家出貨(這個時間可能比較長一些,莊家吸籌時間越長,出貨時間就長) ,看看寰島走勢(在第一次放量就要先出貨了)假如前期是經過盤整的股票, (目前個人認為有寶新能源)在突破勁線或阻力線時放量就可跟進,那才是真真正正的量增價升下跌不是一定要放量,而縮量下跌後果更嚴重,主要是因為前期莊家已出完貨,利用剩餘數量再砸一下盤,散戶就會損失慘重!About half of liver infarcts occur with arteritis, and the remaining half are due to a variety of causes
大約一半的肝臟梗死出現于動脈炎時,其餘半數的病因多樣。Essentially true story of how spartan king leonidis led an extremely small army of greek soldiers ( 300 of them his personal body guards from sparta ) to hold off an invading persian army more than 20 times as large
講述了斯巴達王里奧尼迪斯如何率領數量極少的希臘士兵( 300名他的侍衛)阻止20餘倍的波斯敵軍入侵的真實故事。He knew the rest of the catalogue.
餘下的他都心裏有數。A proportion of the samples are sent to the epds environmental microbiology laboratory where they receive same - day analyses for e. coli, faecal coliforms, and 5 - day biochemical oxygen demand. the remainder of the samples are stored in a cold room before being delivered to the government laboratory, where they are analysed according to the 39 other parameters outlined in chapter 2
部分樣本會送往署內的環境微生物學化驗室即日進行大腸桿菌糞大腸菌群和五天生化需氧量分析,其餘樣本則先存放于冷凍室,稍後送交政府化驗所,根據第二章所述進行39項其他參數的分析。We derive the addition formulas for sine and cosine from the arithmetic of complex numbers.
用復數算術推導了正弦,餘弦的加法公式。The expression for g can be rewritten in terms of trigonometric sines and cosines.
關于g的表達式可以重寫成三角函數的正弦和餘弦形式。Finite point matrix method based on cosine spline
基於餘弦樣條函數的有限點陣法A few stars are known which are hardly bigger than the earth, but the majority are so large that hundreds of thousands of earths could be packed inside each and leave room to spare ; here and there we come upon a giant star large enough to contain millions of millions of earths
人們所知道的幾個星球並不比地球大多少,但絕大多數的星球卻大得足以容納成千上萬個地球還綽綽有餘;我們到處都能遇見大得足以包容千千萬萬個地球的巨星。Then, the associated search optimal algorithm based on virtual avl tree is promoted to rapidly reconstruct the half - edge topological structure. 3. to rebuild the tooth surface from the littery measure data, the membrane deformation algorithm based on loop subdivision is given to fit density triangle meshes to subdivision surface
前者巧妙、高效地完成了去除冗餘點的工作,將stl數據的存儲尺寸壓縮為原來的18 % 25 % ;後者完成了數據的半邊拓撲重建,使得后續對于邊界邊搜索、 1環鄰域搜索顯示出較好的優勢,實現了三角網格模型的快速拓撲重建。Generally, this problem is reduced to quadratic residue problem of modulo a big prime number
一般而言,該問題歸結為模大素數的二次剩餘問題,但這種歸結不能用於最優擴域oef 。The remaining notes will be allocated to applicants pro rata rounded down to the nearest whole note. notes remaining after rounding will be allocated by ballot
餘下的債券如有會根據每位申請人所申請的債券的餘下未獲配發數量,按比例配發予每位申請人,倘不足一份債券,則向下調整至整數。Notes remaining will be allocated to each application on a pro rata basis to the remaining quantity of notes applied for by each application, rounded down to the nearest whole note and in the case of notes remaining after rounding, by ballot
餘下的債券將會根據每份申請所申請債券的餘下未獲配發數量,按比例配發予每份申請若不足一份債券,將向下調整至整數。若向下調整至整數后仍有剩餘債券,則會以抽簽方式配發。Then data integration among classes is solved under product information as a medium among them. finally, to decrease the redundance, the table of database is designed relatively and the field is designed with information of production attribute changed
為了提高系統的處理事物的能力以及盡可能地避免數據冗餘,數據庫表作了關聯性設計,並將產品屬性的變化信息引進數據結構的設計中。The wheat growing area in central shaanxi was divided into three climatic zones based on the data of climatic factors and the disease severity for 20 years by using progressive discriminatory analysis
利用20餘年的氣候資料和病情數據,以逐步判別分析法將關中麥區各縣(市)劃分為三大氣候區。Abstract : the wheat growing area in central shaanxi was divided into three climatic zones based on the data of climatic factors and the disease severity for 20 years by using progressive discriminatory analysis
文摘:利用20餘年的氣候資料和病情數據,以逐步判別分析法將關中麥區各縣(市)劃分為三大氣候區。On the base of above it, this paper discuss the synthesis of optimum distributed arrays by nonuniform spacing in the sense of dolph - chebyshev. having derived the equations of optimum element distribution, we analyze the exponentially spaced array, which are optimum when the elements are isotropic and equally weighted, and the array by general raised cosine function. the formulate for estimating the sidelobe envelope, beamwidth of the array pattern and clean region width are obtained
推導了最佳陣元分佈方程,分別對陣元無方向性和等加權時的最佳分散式陣列? ?指數間隔陣列和採用廣義升餘弦加權的最佳分散式陣列進行了分析,推導了天線方向圖旁瓣包絡、波束寬度,干凈掃描區寬度的估計公式,給出了近軸旁瓣電平與陣列參數的關系。Integer division returns the quotient, that is, the integer that represents the number of times the divisor can divide into the dividend without consideration of any remainder
整除會返回商數,它是一個整數,表示在不考慮有餘數的情況下,除數可以除被除數的次數。If her employer only paid back $ 18, 000, she may claim a deduction for the balance of $ 12, 000
如獲發還18 , 000元,她可在其報稅表上申請扣除餘數的12 , 000元。分享友人