餘數的 的英文怎麼說

中文拼音 [shǔde]
餘數的 英文
odd
  • : Ⅰ同「余」Ⅰ-Ⅳ1. Ⅱ名詞(姓氏) a surname
  • : 數副詞(屢次) frequently; repeatedly
  • : 4次方是 The fourth power of 2 is direction
  1. They represent 38. 1 % of the total species that have been identified. we performed preliminary study on those mycofiora of agarics under those forests. based on our study, we identified one tropical element family : entolomataceae, two north temperate element families : hygrophoraceae and cortinariaceae ; the other 11 families all belong to cosmopolitan element

    根據論文所研究傘菌類群,從科地理分佈看,熱帶亞熱帶成分只有粉褶菌科entolomataceae一科;北溫帶成分科有兩個,即蠟傘科hygrophoraceae和絲膜菌科;其科均為世界廣布科,占總科78 . 6 。
  2. After like near future arrowroot continent dam flies a shop sign afresh go situation and to the limit of one ' s capacity rises should notice early days goes situation, if be pulled considerably, magnify again quantity, be about vigilance is banker shipment ( this time may be a few longer, banker is sucked prepare time to grow more, shipment time is long ), island visitting extensive region goes situation ( be about in first time to the limit of one ' s capacity first shipment ) if early days is to pass dish of full share, ( at present the individual thinks to have treasure new the sources of energy ) in the to the limit of one ' s capacity when breaking through strong line or resistance line but follow - up, that ability is really true the quantity adds valence to rise dropping is not must to the limit of one ' s capacity, and shrink the volume drops consequence is more serious, because early days banker already gave money, basically be, use odd amount to be bungled again dish, medicinal powder door meet disastrous

    如近期葛洲壩重新開牌后走勢而放量上升要注重前期走勢,假如大幅拉升后再放大量,就要警惕是莊家出貨(這個時間可能比較長一些,莊家吸籌時間越長,出貨時間就長) ,看看寰島走勢(在第一次放量就要先出貨了)假如前期是經過盤整股票, (目前個人認為有寶新能源)在突破勁線或阻力線時放量就可跟進,那才是真真正正量增價升下跌不是一定要放量,而縮量下跌後果更嚴重,主要是因為前期莊家已出完貨,利用剩量再砸一下盤,散戶就會損失慘重!
  3. About half of liver infarcts occur with arteritis, and the remaining half are due to a variety of causes

    大約一半肝臟梗死出現于動脈炎時,其病因多樣。
  4. Essentially true story of how spartan king leonidis led an extremely small army of greek soldiers ( 300 of them his personal body guards from sparta ) to hold off an invading persian army more than 20 times as large

    講述了斯巴達王里奧尼迪斯如何率領量極少希臘士兵( 300名他侍衛)阻止20波斯敵軍入侵真實故事。
  5. He knew the rest of the catalogue.

    他都心裏有
  6. A proportion of the samples are sent to the epds environmental microbiology laboratory where they receive same - day analyses for e. coli, faecal coliforms, and 5 - day biochemical oxygen demand. the remainder of the samples are stored in a cold room before being delivered to the government laboratory, where they are analysed according to the 39 other parameters outlined in chapter 2

    部分樣本會送往署內環境微生物學化驗室即日進行大腸桿菌糞大腸菌群和五天生化需氧量分析,其樣本則先存放于冷凍室,稍後送交政府化驗所,根據第二章所述進行39項其他參分析。
  7. We derive the addition formulas for sine and cosine from the arithmetic of complex numbers.

    用復算術推導了正弦,加法公式。
  8. The expression for g can be rewritten in terms of trigonometric sines and cosines.

    關于g表達式可以重寫成三角函正弦和弦形式。
  9. Finite point matrix method based on cosine spline

    基於弦樣條函有限點陣法
  10. A few stars are known which are hardly bigger than the earth, but the majority are so large that hundreds of thousands of earths could be packed inside each and leave room to spare ; here and there we come upon a giant star large enough to contain millions of millions of earths

    人們所知道幾個星球並不比地球大多少,但絕大多星球卻大得足以容納成千上萬個地球還綽綽有;我們到處都能遇見大得足以包容千千萬萬個地球巨星。
  11. Then, the associated search optimal algorithm based on virtual avl tree is promoted to rapidly reconstruct the half - edge topological structure. 3. to rebuild the tooth surface from the littery measure data, the membrane deformation algorithm based on loop subdivision is given to fit density triangle meshes to subdivision surface

    前者巧妙、高效地完成了去除冗工作,將stl存儲尺寸壓縮為原來18 % 25 % ;後者完成了半邊拓撲重建,使得后續對于邊界邊搜索、 1環鄰域搜索顯示出較好優勢,實現了三角網格模型快速拓撲重建。
  12. Generally, this problem is reduced to quadratic residue problem of modulo a big prime number

    一般而言,該問題歸結為模大素二次剩問題,但這種歸結不能用於最優擴域oef 。
  13. The remaining notes will be allocated to applicants pro rata rounded down to the nearest whole note. notes remaining after rounding will be allocated by ballot

    債券如有會根據每位申請人所申請債券下未獲配發量,按比例配發予每位申請人,倘不足一份債券,則向下調整至整
  14. Notes remaining will be allocated to each application on a pro rata basis to the remaining quantity of notes applied for by each application, rounded down to the nearest whole note and in the case of notes remaining after rounding, by ballot

    債券將會根據每份申請所申請債券下未獲配發量,按比例配發予每份申請若不足一份債券,將向下調整至整。若向下調整至整后仍有剩債券,則會以抽簽方式配發。
  15. Then data integration among classes is solved under product information as a medium among them. finally, to decrease the redundance, the table of database is designed relatively and the field is designed with information of production attribute changed

    為了提高系統處理事物能力以及盡可能地避免據冗據庫表作了關聯性設計,並將產品屬性變化信息引進據結構設計中。
  16. The wheat growing area in central shaanxi was divided into three climatic zones based on the data of climatic factors and the disease severity for 20 years by using progressive discriminatory analysis

    利用20氣候資料和病情據,以逐步判別分析法將關中麥區各縣(市)劃分為三大氣候區。
  17. Abstract : the wheat growing area in central shaanxi was divided into three climatic zones based on the data of climatic factors and the disease severity for 20 years by using progressive discriminatory analysis

    文摘:利用20氣候資料和病情據,以逐步判別分析法將關中麥區各縣(市)劃分為三大氣候區。
  18. On the base of above it, this paper discuss the synthesis of optimum distributed arrays by nonuniform spacing in the sense of dolph - chebyshev. having derived the equations of optimum element distribution, we analyze the exponentially spaced array, which are optimum when the elements are isotropic and equally weighted, and the array by general raised cosine function. the formulate for estimating the sidelobe envelope, beamwidth of the array pattern and clean region width are obtained

    推導了最佳陣元分佈方程,分別對陣元無方向性和等加權時最佳分散式陣列? ?指間隔陣列和採用廣義升弦加權最佳分散式陣列進行了分析,推導了天線方向圖旁瓣包絡、波束寬度,干凈掃描區寬度估計公式,給出了近軸旁瓣電平與陣列參關系。
  19. Integer division returns the quotient, that is, the integer that represents the number of times the divisor can divide into the dividend without consideration of any remainder

    整除會返回商,它是一個整,表示在不考慮有餘數的情況下,除可以除被除
  20. If her employer only paid back $ 18, 000, she may claim a deduction for the balance of $ 12, 000

    如獲發還18 , 000元,她可在其報稅表上申請扣除餘數的12 , 000元。
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