右運算 的英文怎麼說
中文拼音 [yòuyùnsuàn]
右運算
英文
right operation-
Structure to the right of the subtraction operator
減法運算符右側的源The panel on the left will hold the calculator buttons and display, and the panel on the right will show a record of the arithmetic operations performed by the user
控制項分成兩個面板。左側的面板包含計算器按鈕和顯示器,右側面板顯示用戶執行的算術運算的記錄。In an arithmetic right shift, the bits shifted beyond the rightmost bit position are discarded, and the leftmost bit is propagated into the bit positions vacated at the left
在算術右移位運算中,將丟棄移出最右側數位位置的數位,並將最左側的數位傳播到左端空出的數位位置。The following assignment statement will produce a compilation error because the arithmetic expression on the right - hand side of the assignment operator evaluates to
以下賦值語句將產生一個編譯錯誤,原因是賦值運算符右側的算術表達式默認情況下計算結果為Left - associative operators are evaluated in order from left to right
左結合運算符按從左到右的順序計算。Right - associative operators are evaluated in order from right to left
右結合運算符按從右到左的順序計算。Both the left and right operands of the apply operator are table expressions
Apply運算符的左操作數和右操作數都是表表達式。A binary operator is an operator that uses two operands, usually termed the left and right operands
二元運算符是使用兩個操作數的運算符,這兩個操作數通常稱為左操作數和右操作數。A important result abrout the left - infinitesimal operator and the right - resolvent operator of a two - parameters semigraoup
雙參數半群的左無窮小運算元和右預解運算元的一個重要結果In this dissertation, the research trends for the problem have been introduced ; the ‘ dim ’ and ‘ point ’ has been strictly defined in mathematics from machine vision and human vision ; the ideal clutter suppression system based on clutter predication and the realization and evaluation of evaluation index has been studied, in succession the clutter suppression technologies have been researched. firstly, the classic nonparametric algorithm has been analyzed in detail and systematically, for it ’ s weakness that it cannot remove the non - stationary clutter ideally, kalman filter algorithm for clutter suppression in 2d image signal has been built. secondly, fast adaptive kalman filter is presented based on fast wide - sense stationary areas partition algorithm : limited combination and division algorithm based on quarti - tree algorithm, new taxis filter route algorithm which can break through the limitation of the necessity of pixel neighborhood of 2d filter and laplace data model with two parameters which is perfectly suitable for the residual image of kalman clutter suppression
首先分析了經典的非參數法,對於四種具有代表性的核,從前述的三個性能評價方面做了分析和對比,指出了其速度快的優點和對非平穩圖像適應性差的弱點,針對非參數法的弱點,重點研究了對非平穩圖像適應良好的卡爾曼雜波抑制技術:建立了非平穩圖像的類自回歸模型,在此基礎上建立了二維卡爾曼濾波基礎的兩個方程:狀態方程和測量方程;建立了非平穩圖像準平穩區域快速劃分演算法:基於四叉樹法的有限分裂合併演算法;二維空間的基於k排序的濾波路線演算法,突破了空域濾波路線上區域相鄰的限制;在這些研究的基礎上實現了快速卡爾曼估計,實驗驗證了該方法相對逐點卡爾曼估計可以提高運算速度三倍左右;雜波抑制結果表明傳統的高斯性檢驗並不適合卡爾曼估計后的殘余圖像,由此建立了殘余圖像的雙參數拉普拉斯模型,實驗表明其可以完好的吻合殘余圖像的概率密度曲線。The unsigned right - shift operator shifts its first operand right by the number of bits specified by its second operand. expr count
無符號的右移位運算符( > > > )將第一個操作數向右移動第二個操作數指定的位數。In an arithmetic right shift, the bits shifted beyond the rightmost bit position are discarded, and the leftmost sign bit is propagated into the bit positions vacated at the left
在數學右移位運算中,將丟棄移出最右側數位位置的數位,並將最左側的(符號)數位傳播到左端空出的數位位置。On the right side of the subtraction operator
減法運算符右側的Gets or sets the code expression on the right of the operator
獲取或設置運算符右邊的代碼表達式。Structure on the right of the equality operator
相等運算符右側的Structure to the right of the equality operator
相等運算符右側的So, for some, we can judge whether the linear partial differential operators p ( d ) admit a right inverse according to the boundary condition
由此,對某些n ,可以根據其邊界的幾何性態來荊斷其上的偏徽分運算元屍( d )是不存在右逆的Dongfeng peugeot citroen, established in 1992, was the third sino - foreign auto joint venture established in the country after volkswagen s two earlier ventures. amidst declining sales, dongfeng and psa peugeot citroen announced last year that they planned to invest 600 million euros us 972 million to double annual manufacturing capacity to 300, 000 units by 2006
北京市目前每年的地鐵補貼都在7億元人民幣左右,如果發展到300公里,僅按照簡單的比例運算,每年財政在地鐵上的補貼都會達到40億50億元,這將對城市的可持續發展造成巨大影響。Does not compare equal because the division operation on the left - hand side has maximum precision while the constant on the right - hand side is only precise to the specified digits
的比較結果為不相等,因為左側的除法運算具有最大精度,而右側的常數僅精確到指定位。The second section discusses properties of left - invertible and right - invertible operator in use of mbekhta ' s subspaces and gives the necessary and sufficent condition. i get results as follows : theorem 2. 6 suppose a b ( x ) is the left - invertible
第二節主要運用mbekhta子空間討論左可逆和右可逆運算元的性質,並給出運算元可逆的充要條件,得到下面的定理:定理26設aeb ( x )為左可逆運算元分享友人