旋轉鉆井法 的英文怎麼說

中文拼音 [xuánzhuǎnzhēnjǐng]
旋轉鉆井法 英文
rotary drilling
  • : 旋Ⅰ動詞1 (旋轉) whirl 2 (用車床切削或用刀子轉著圈地削) turn sth on a lathe; lathe; pare Ⅱ名詞...
  • : 轉構詞成分。
  • : 鉆Ⅰ名詞1. (打眼用的工具) drill; auger 2. (指鉆石) diamond; jewel Ⅱ動詞(用尖物在另一物體上轉動) drill; bore
  • : Ⅰ名詞1 (從地面往下鑿成的能取水的深洞) well 2 (形狀像井的東西) sth in the shape of a well 3 (...
  • : Ⅰ名詞1 (由國家制定或認可的行為規則的總稱) law 2 (方法; 方式) way; method; mode; means 3 (標...
  • 旋轉 : revolve; gyrate; rotate; spin ; revolution; revolvement; rotation; circumgyration; circulation
  1. In this article, we use idea of turning dispersion into convergence and put all the well ' s points into the same unit net to think about it. and answer three questions of the distribution of well drilling by the way of searching for groups of points. fincite - step - searching underthe condition of translationg fcoordinate system or revolving coordinate system. to first question. we find two algo - rithms and make use of data that is given to find the solution. we seek coorlinate of net point is co. 361, 0. 461 ) and mostly four old well ' s points are utilized at the same time by first algorithim, which are no. 2, no, 4, no. 5, no. 10. by second algorithm, we rechon the coordinate of net point is co. 390, 0. 505 ). and that mostly four old well ' s points are utilizld which are no. 2, no. 4, no. 10. to second question, we turn it into the first question by angling awt the center of net point. we seek that mostly six old well ' s points are utilized at the same time, which are no. 1, no. 6, no. 7, no. 8, no. 9, no. 11, when net is angled 0. 78 radian. and net point is translated to ( 0. 75, 0. 076 ) ( at nwe coordinate system ). to third question, wefind a necessary and sufficient condition and affer algorithms, at last, we analyse algorithms

    運用化分散為集中的思想,把所有的點都放在同一個單位網格內考慮.在坐標可平移、的條件下,利用尋找點群、有限步驟搜索,對布局的三個問題進行了解答.對問題一,給出了兩個不同演算.並對題目提供的數據進行了求解,演算1得到的結點為( 0 . 361 , 0 . 461 ) ,最多有4個舊點被同時利用,它們是第2 、 4 、 5 、 10個點;演算2得到的結點為( 0 . 390 , 0 . 505 ) ,最多有4個點被利用,它們是第2 、 4 、 5 、 10個點.對問題二,以結點為中心一定的角度后,歸結為問題一進行求解,求解結果為當網格傾斜角為0 . 78弧度(相對原坐標系) ,結點平移到( 0 . 75 , 0 . 076 )點(在新坐標系下) ,可被同時利用的最多舊點為6個,它們是第1 、 6 、 7 、 8 、 9 、 11個點,對問題三,我們給出了充要條件,並給出了演算.最後還分析了演算的優劣性
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