零元 的英文怎麼說

中文拼音 [língyuán]
零元 英文
zero element
  • : Ⅰ數詞1 (零數) zero2 (數的空位) zero sign (0); nought 3 (表示沒有數量;無) nil; nought 4 (...
  1. It is good that the money on credit card puts 500 yuan or so commonly, enough pocket money of a month is good, need not put too much, at ordinary times unused money can be put fixed, or the current account that puts to do not have accessary card this in

    信用卡上的錢一般放500左右就好了,夠一個月花就好了,不必放太多,平時不用的錢可以存定期,或放一本沒有附屬卡的活期帳本里
  2. 1926 an ammunition depot explosion at lake denmark n. j., was triggered by lightning, killing 31persons. sporadic explosions continued for days ; damage reached $ 93 000 000

    位於紐約州萊克登馬克的一座彈藥庫遭電擊引起爆炸, 31人喪生,星爆炸持續了好幾天。損失9 . 300萬美
  3. A very satisfactory answer can be given in terms of the appropriate analytic generalization of the algebraic concept of nilpotence.

    將代數學中的冪零元概念作適當的解析學上的推廣,可以繪出一個很滿意回答。
  4. The input axis of the azimuth gyro under this condition is vertical, and pendulum unit is nulled.

    在這樣情況下方位陀螺的輸入軸是處於垂直位置,同時擺錘單位。
  5. The bending stress is zero for the element at b.

    在B處的單體,彎曲應力為
  6. A determinant whose only nonzero elements occur in square blocks centered about the principal diagonal is in block-diagonal form.

    僅有的非零元素集中於主對角線的方塊中的行列式是分塊對角形式的。
  7. X is killed by some non-zero element of a.

    X被A中某個非零元化。
  8. Almost nilpotent element

    殆冪零元
  9. It is shown that if l is a modular lattice with finite length, and with 0, 1 the least and the largest elements in l respectively, then 1 is the union of some minimal elements in l if and only if 0 is the intersection of some maximal elements in l, if and only if each non - zero element in l is the union of some minimal elements in l. by using these results, we give the necessary and sufficient conditions of an algebra module, module, ring, group and semigroup, respectively, to be semisimple

    最後得出有限生成的ps -系是noetherian ( artinian )系的充要條件是它關于本質子系滿足升鏈(降鏈)條件。第二章給出了一個模格是半單的若干充要條件。得到:有有限長度的模格l上,最大1是若干極小的並當且僅當最小0是若干極大的交,當且僅當l中任意非零元可表示為若干極小的並。
  10. X is killed by some non - zero element of a

    X被a中某個非零元化。
  11. The remuneration for non - executive chairmen of major statutory bodies in hong kong ranges from nil to not more than 1 million

    現時,本港主要法定團體非執行主席的酬金介乎零元至不多於100萬
  12. The remuneration for non - executive chairmen of major statutory bodies in hong kong ranges from nil to not more than $ 1 million

    現時,本港主要法定團體非執行主席的酬金介乎零元至不多於100萬
  13. The construction of least radical without nilpotent element of ring

    環的最小無冪零元根的構造
  14. But when the condition number of the matrix is very large, the round error will be accumulated to collapse the true solution, that is, the method is unstable

    同時,當系數矩陣的非零元結構不規則或帶寬較大時,其計算量與存儲量十分大。
  15. Some properties of the quasi diagonally dominant matrix with chain of non - zero elements

    擬具非零元素鏈對角占優矩陣的若干性質
  16. If this constructor does not require parameters, pass an array with zero elements, as in object parameters new object 0

    如果此構造函數不需要參數,則像object [ ] parameters = new object [ 0 ]中那樣傳遞一個包含零元素的數組。
  17. Based on this method, matrix variation basis of the algorithm is forther discussed for voiding useless operations of zero elements multiplication

    在此基礎上,探討了避免矩陣中零元素相乘的無效操作,莫定了該演算法的矩陣變換基礎。
  18. All nonzero elements of gf ( 2m ) must be verified by the conventional step - by - step decoding algorithm, which increases the computational complexity of decoding, so the conventional step - by - step decoding algorithm ca n ' t be adapt to the requirement of rapid decoding

    因此標準的step - by - step譯碼演算法對gf ( 2 ~ m )域中所有的非零元素全部檢驗,將造成計算量巨大,難以滿足快速譯碼的要求。本論文基於t
  19. And then, a state equation is set up by the relationship among the input and output characteristic vectors as well as the state matrices ( sms ). the non - zero element in the sms characteristic is taken according to taylor series expansion, which is a transfer function of the basic mechanical unit

    再次,闡述了狀態變換矩陣的形成過程,通過泰勒級數展開,提取其非零元素的特徵,並按照傳遞特徵值對基本變換單加以分類,歸納了狀態變換矩陣的性質。
  20. But conventional step - by - step decoding algorithm requires that every symbol of received word r ( x ) orderly adds to 2m - 1 nonzero elements of gf ( 2 ) to determine whether the weight of the error pattern has been reduced. if the weight of error pattern is reduced, the error location and the corresponding error value are found

    但是標準的step - by - step譯碼演算法將接收碼字中每個符號與伽羅華域gf ( 2 ~ m )中的2 ~ m - 1個非零元素依次相加,判斷錯誤圖樣的重量是否下降,如果下降則說明找到了錯誤位置和相應的錯誤值。
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