orbit shape 中文意思是什麼
orbit shape
解釋
軌道形狀-
The tilt of the earth's axis, not the shape of its orbit, is what is responsible for the seasons.
形成季節的主要因素不是地球公轉軌道的形狀，而是地球自轉軸的傾斜。 -
" we started by playing with the size and shape of the orbit and the tilt of the spinning galaxies
我們開始著手的是軌道的大小和形狀以及旋轉著的星系的傾斜度。 -
It is not suitable for geodetic and geodynamic study, which requires a regular shape, small area - to - mass ratio, precise tracking capabilities resulting in cm orbit accuracy, negligible slew times and long operational life ( 10 - 15 years )
後者要求衛星有較規則的外形、較小的面質比和較長的壽命，其定軌精度應達到與觀測精度相當的水平（好於幾cm ） 。 -
1 a planet is a celestial body that is in orbit around the sun, has sufficient mass for its self - gravity to overcome rigid body forces so that it assumes a hydrostatic equilibrium nearly round shape, and has cleared the neighbourhood around its orbit
1 .行星是指符合以下特性的天體： a在圍繞著太陽的軌道上運行b有足夠質量以產生引力達至流體靜力平衡的形狀近似球形及c已使其軌道附近清空。 -
2 a dwarf planet is a celestial body that is in orbit around the sun, has sufficient mass for its self - gravity to overcome rigid body forces so that it assumes a hydrostatic equilibrium nearly round shape, has not cleared the neighbourhood around its orbit, and is not a satellite
2 .矮行星是指符合以下特性的天體： a在圍繞著太陽的軌道上運行b有足夠質量以產生引力達至流體靜力平衡的形狀近似球形c沒有使其軌道附近清空及d不是衛星。 -
According to the new rules for a planet adopted at an international astronomical union meeting in prague, pluto doesn ' t make the grade for a planet : " a celestial body that is in orbit around the sun, has sufficient mass for its self - gravity to overcome rigid body forces so that it assumes a nearly round shape, and has cleared the neighborhood around its orbit. " pluto is automatically disqualified because its oblong orbit overlaps with neptune ' s
根據在布拉格舉行的國際天文聯合會會議通過的行星新定義，冥王星達不到行星的級別，即：在繞太陽的軌道上運轉的天體，體積足夠大使其自身的重力可以克服其剛體力呈近似圓球狀，且能夠清除其軌道附近的其他天體。 -
But the shape of vsop satellite is quite irregular, with a large a / m and a short operational life ( 5 years ). the orbit determination of halca is accurate to 2 - 5 m ( frey 2002 ), and it is quite difficult to be accurate to 10 cm
而vsop的外形極不規則，面質比較大，壽命估計只有5年，其定軌精度的實驗估計值為幾米（ frey2002 ） ，很難達到10cm的水平。
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