stack element 中文意思是什麼
stack element
解釋
堆棧單元-
In the proposed join algorithms, although some algorithms such as mpmgin algorithm [ 23 ], outperform standard rdbms join algorithms, they perform a lot of unnecessary computation and i / o for matching basic structural relationships, especially in the case of parent - child relationships ; other algorithms such as the stack - tree - desc algorithm [ 24 ], represent the state - of - the - art in structural joins, however, they do not utilize indexed structures but sequentially scan the input lists. thus, i / o ' s can be wasted for scanning element that do not participate in the join, and join speed can be influenced
另外，在所提出的演算法中，盡管有的演算法，如mpmgjn演算法[ 23 ]優于標準的rdbms連接演算法，但是該演算法為匹配基本的結構關系，特別是在父子關系情況下，執行了大量不必要的計算和佔用了大量的i / o資源；有的演算法雖然代表了結構連接演算法的先進水平，如stack - tree - desc [ 24 ]連接演算法，但是它沒有利用索引結構而是順序瀏覽輸入列表。 -
Performance for a piezoresistive transducer pressure sensor to thermal and pressure environments can be predicted by finite element method. a simplified 1 / 8 model, considering silicon dioxide and nitride process as well as stack anodic bonding and adhesive bonding processes, was developed. the fem results were found to be comparable to experimental data. case studies suggested that pyrex stack induces certain amount of non - linearity, while it isolates hard epoxy nonlinear effect. flexible epoxy bonding or soft adhesive bonding is preferred to the packaging process. the viscoelasticity and viscoplasticity of bonding material will result in hysteresis and drift errors to sensor output. however, soft adhesive s influence on sensor can be ignored under relative stable environments. more over, detailed design and process information will help to improve modeling application
熱、壓環境下壓阻變換壓力傳感器的性能可以通過有限元方法預測.這里研究了簡化的1 / 8模型，模型考慮了二氧化硅和氮化硅生成過程及堆陽極鍵合和膠粘結合過程.結果發現有限元預測結果和實驗數據具有可比性.範例研究表明，硼硅堆導致產生一定的非線性，但它隔離了硬環氧樹脂的非線性.在包裝過程中最好使用柔性環氧黏合或軟黏膠性結合.黏合材料的黏彈性和黏塑性將會導致傳感器輸出的滯后和漂移誤差.然而，在相對穩定的環境下，軟黏合劑對傳感器的影響可以忽略.此外，詳細的設計和過程信息有助於提高模型的適用性 -
Has to be created, the jvm needs to say " freeze, i want an nice picture of you now, so stop that pushing and popping and smile nicely until i m done. " a stack trace doesn t just contain one or two elements from the stack, it contains every element, from top to bottom, with line numbers and everything
時， jvm不得不說： 「先別動，我想就您現在的樣子存一份快照，所以暫時停止入棧和出棧操作，笑著等我拍完快照吧。 」棧跟蹤不只包含運行時棧中的一兩個元素，而是包含這個棧中的每一個元素，從棧頂到棧底，還有行號和一切應有的東西。 -
Instruction removes the top element from the stack
指令從堆棧中移除頂部元素。 -
When an exit address is encountered, the current active function has returned and the top element on the stack is discarded
在碰到退出函數時，當前的活動函數就會返回，並釋放棧頂元素。 -
Finishes, this privileged element is popped off the stack and any call to
執行完，這個privileged元素就彈出堆棧，而對 -
Instruction duplicates the top element of the stack, and leaves two identical values atop it
指令重復堆棧的頂層元素，並且將兩個相等值留在堆棧頂部。 -
Essentially returns the call stack going only up to this topmost privileged element ; hence, the information about the authenticated
的調用返回直到這個最高privileged元素的調用堆棧，因此，有關認證的 -
1. on the bases of some basic suppositions, terzaghi ' s one dimensional consolidation and principles of layered summation method, the paper draw the formula which can calculate the embankment of layered filling and take the formula into programme ; 2. building the finite difference model of layered high - stack soil, carrying out numerical simulation of construction sequence, construction velocity, interface element of layer - stacked, the author get the numerical solution
1利用一些基本假定，根據太沙基一維固結理論和分層總和法的基本原理，推導出來計算分層填築體自身沉降的公式，並編制了程序； 2建立了分層填築高填方路堤問題的有限差分模型，並對分層填築的施工順序、施工速度，界面單元進行了數值模擬，獲得了位移場和應力場的數值解。 -
Almost assuredly, any xml parser you use, sax or otherwise, is going to use an internal stack structure to track which element it s currently parsing so that it can issue
如果考慮只有元素的簡化情況，那麼解決方案的第一部分不涉及任何復雜的操作。每當遇到一個新元素時，就在 -
State 0 represents the empty stack, state 1 represents the stack with only one element
狀態0表示空堆棧，狀態1表示只有一個元素：
分享友人