subalgebra 中文意思是什麼
subalgebra
解釋
子代數-
Let d be a nonzero k - vector space of commuting - derivations of a. kaim - ing zhao and yucai su studied the associative algebra a [ d ] = ak [ d ] of weyl type constructed from the pair of a commutative associative algebra. 4 and its commutative derivation subalgebra d over a field k of arbitrary characteristic
趙開明和蘇育才研究了任意特徵的域上具有單位元的交換結合代數a和它的交換導子的子空間d所構造的weyl型代數。他們證明了a [ d ]是單lie代數的充分必要條件是a是d -單的且k _ 1 [ d ]忠實地作用在a上。 -
We can give different structures on a tensor product h q to make it a bialgebra or hopf algebra. in [ 1 ] radford constructed a hopf algebra a x h with the smash algebra structure and the smash coproduct coalgebra structure, and pointed out that if a bialgebra b has a hopf subalgebra h and a projection ! : b - - > h, then there must be a subalgebra a of b such that b @ a x h is a bialgebra isomorphism
在張量積hq上可以給出不同的構造，使它成為雙代數或hopf代數， radford在文獻[ 1 ]中構造了以smash積為代數結構，余smash積為余代數結構的hopf代數a h ，並指出若b是雙代數， h是b的子hopf代數，且存在投射： b h （即是雙代數同態，且| _ h = id _ h ） ，則一定存在b的子代數a ，使ba h是雙代數同構。 -
We prove that m has property ( p ) if and only if ( 11 ) let m be as in ( 10 ) then m and every weakly closed subspace including m have proverty ( p ) if and only if for any t b ( h }, there exist x, y h. such that ( 12 ) let a be a completely distributive subspace lattice algebra acting on a hilbert space, then the rank one subalgebra of a is dense in a if and only if, the weak closures of the first and the second preannihilators of a in the space of all trace class operators are reflexive
一弱閉運算元空間，稱州具有性質（ p ） ，如果州中秩一運算元生成的子空間在期中a一弱稠密.我們證得:川具有性質（ p ） ，等價于州: = { t丁扭） : tx任[州上習， z任火} . （ ll ）設川如（ l0 ）所述，則川以及包含川的每個a一弱閉子空間都具有性質（ p ） ，當且僅當，對任意t任側喲，都存在x ， ，任火使得t一x y州 -
The basic properties of matrix subalgebra were investiaged, the matrix subalgebra was generated by a single matrix, all maximal ideals were classified, the necessary and sufficient conditions for the subalgebra to be semisimple algebra were given
摘要研究了由一個矩陣生成的拒陣子代數的基本性質，給出了其極大理想的完全分類及這類子代數是半單代數的充要條件。 -
In section 2. 2, we prove that if the set of arrows in a quiver is not empty, then nq is not semisimple. we construct the nonsovable subalgebra of nq when there is no less than one circle whose length is bigger than one, and there is no loop in quiver q, thus leads to a conclusion that nq is nonsovable. using the index arrays to discuss the operation of necklace word. construct a sovable subalgebra of nq, which is not nilpotent. this shows that nq is not nilpotent provided that there is a cyclic with length bigger than 1
當箭圖中有長度大於1的循環，且無圈時，構造了n _ q的非可解子代數，從而證明了n _ q是不可解李代數。我們還利用指標數組討論了項鏈字的運算，構造了n _ q的可解非冪零子代數，從而證明了當箭圖中有長度大於1的循環時，項鏈李代數非冪零。在2
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