傾斜中點坐標 的英文怎麼說
中文拼音 [qīngxiézhōngdiǎnzuòbiāo]
傾斜中點坐標
英文
slant midpoint coordinates-
In this article, we use idea of turning dispersion into convergence and put all the well ' s points into the same unit net to think about it. and answer three questions of the distribution of well drilling by the way of searching for groups of points. fincite - step - searching underthe condition of translationg fcoordinate system or revolving coordinate system. to first question. we find two algo - rithms and make use of data that is given to find the solution. we seek coorlinate of net point is co. 361, 0. 461 ) and mostly four old well ' s points are utilized at the same time by first algorithim, which are no. 2, no, 4, no. 5, no. 10. by second algorithm, we rechon the coordinate of net point is co. 390, 0. 505 ). and that mostly four old well ' s points are utilizld which are no. 2, no. 4, no. 10. to second question, we turn it into the first question by angling awt the center of net point. we seek that mostly six old well ' s points are utilized at the same time, which are no. 1, no. 6, no. 7, no. 8, no. 9, no. 11, when net is angled 0. 78 radian. and net point is translated to ( 0. 75, 0. 076 ) ( at nwe coordinate system ). to third question, wefind a necessary and sufficient condition and affer algorithms, at last, we analyse algorithms
運用化分散為集中的思想，把所有的井點都放在同一個單位網格內考慮.在坐標可平移、旋轉的條件下，利用尋找點群、有限步驟搜索法，對鉆井布局的三個問題進行了解答.對問題一，給出了兩個不同演算法.並對題目提供的數據進行了求解，演算法1得到的結點為（ 0 . 361 ， 0 . 461 ） ，最多有4個舊井點被同時利用，它們是第2 、 4 、 5 、 10個井點;演算法2得到的結點為（ 0 . 390 ， 0 . 505 ） ，最多有4個井點被利用，它們是第2 、 4 、 5 、 10個井點.對問題二，以結點為中心旋轉一定的角度后，歸結為問題一進行求解，求解結果為當網格傾斜角為0 . 78弧度（相對原坐標系） ，結點平移到（ 0 . 75 ， 0 . 076 ）點（在新坐標系下） ，可被同時利用的最多舊井點為6個，它們是第1 、 6 、 7 、 8 、 9 、 11個井點，對問題三，我們給出了充要條件，並給出了演算法.最後還分析了演算法的優劣性
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