給出理由 的英文怎麼說

中文拼音 [gěichūyóu]
給出理由 英文
give the cause
  • : 給Ⅰ動詞1 (送對方某物; 使對方得到) give; grant 2 (用在動詞后 表示交與 付出) pass; pay 3 (叫; ...
  • : Ⅰ名詞1 (物質組織的條紋) texture; grain (in wood skin etc ) 2 (道理;事理) reason; logic; tru...
  • : causereason
  • 給出 : give
  • 理由 : account; regard; justification; reason; ground; argument
  1. In this thesis, we study some open problems and conjectures about the linear complementarity problem. it consists of the next three aspects : firstly, we study murthys " open problem whether the augmented matrix is a q0 - matrix for an arbitary square matrix a, provide an affirmable answer to this problem, obtain the augmented matrix of a sufficient matrix is a sufficient matrix and prove the graves algorithm can be used to solve linear complementarity problem with bisymmetry po - matrices ; secondly, we study murthys " conjecture about positive semidefinite matrices and provide some sufficient conditions such that a matrix is a positive semidefinite matrix, we also study pang ' s conjecture, obtain two conditions when r0 - matrices and q - matrices are equivelent and some properties about e0 q - matrices ; lastly, we give a counterexample to prove danao ' s conjecture that if a is a po - matrix, a e " a p1 * is false, point out some mistakes of murthys in [ 20 ], obtain when n = 2 or 3, a e " a p1 *, i. e. the condition of theorem 3. 2 of [ 25 ] that a p0 can be deleted and obtain a e " a is an almost e - matrix if a is a co - matrix or column sufficient matrix

    本文分為三個部分,主要研究了線性互補問題的幾個相關的公開問題以及猜想: ( 1 )研究了murthy等在[ 2 ]中提的公開問題,即對任意的矩陣a ,其擴充矩陣是否為q _ 0 -矩陣,了肯定的回答,得到充分矩陣的擴充矩陣是充分矩陣,並討論了graves演算法,證明了若a是雙對稱的p _ 0 -矩陣時, lcp ( q , a )可graves演算法; ( 2 )研究了murthy等在[ 6 ]中提關於半正定矩陣的猜想,了半正定矩陣的一些充分條件,並研究了pang ~ -猜想,得到了只r _ 0 -矩陣與q -矩陣的二個等價條件,以及e _ 0 q -矩陣的一些性質; ( 3 )研究了danao在[ 25 ]中提的danao猜想,即,若a為p _ 0 -矩陣,則,我們了反例證明了此猜想當n 4時不成立,指了murthy等在[ 20 ]中的一些錯誤,得到n = 2 , 3時,即[ 25 ]中定3 . 2中a p _ 0的條件可以去掉。
  2. By using the processing method of sliding time window, the problem of the periodicity range ambiguity is solved. meanwhile, the problem of range ambiguity which is produced because the range of target is biger than the maximum range of radar is also solved by using this method. then, the pulse width parameter which is the most important in the parameters of fmicw is analyzed. the stricter restrict is given to ensure the range spectrum has only one beat frequency after signal processing. at last this thesis introduces the different signal processing methods of fmpcw and fmicw

    同時利用該方法解決了fmpcw信號的於目標距離超過雷達的最大單值測距范圍而引起的距離模糊問題。然後對fmicw波形參數中最為重要的脈沖寬度進行了分析,了更為嚴格的約束條件,保證了信號處后距離譜峰值的唯一性。最後,分別介紹了fmpcw和fmicw信號的不同處方式,並對兩者不同的時域濾波性能進行了比較,並對二者的差異進行了分析。
  3. The scale effects due to unsimilar bed risistance is discussed in detail, and the correct way of scour depth is supposed. at last, a new transport rate formulas of uniform or nonuniform bed load is given

    本文還對於阻力不相似而引起的比尺效應進行了較詳細的討論,從論上了沖刷深度比尺效應的修正方法及新的均勻、非均勻推移質輸沙率的計算公式。
  4. By applying the th model theory to analyzing the cases of developed countries that mentioned in chapter 4, chapter 6 finds out the block gene and tendon compages that consists of the university - government - industry th. furthermore, it gives the pheno - types as some external expressions of the genotypes and the family - tree diagram constituted by these phenotypes. after a transition, it illuminates the scientometric, the webometric and the triple helix algorithm and their application

    第六章運用th模型論對第四章提供的案例挖掘梳后,發現並了:構成大學?政府?產業三重螺旋體的完整板塊配基和鍵鏈組合,作為「基因型」外在表達的一些「現象型」屬類以及它們所構成的圖式譜系。
  5. So far, the main frame of the conjugation of betrand are established, on the basis of which, it is given that the primary condition the directrix line must be satisfied, the relative curvature of the conjugating surfaces, the relations between non - interventional condition and curvature axle of the directrix line, and so on. the transmission of normal circular - arc gear is a typical bertrand conjugation. in order to promote the transformation from theory to technology, the general principle of this kind of transmission is studied

    為了使研究更加貼近於工程,便於解析處,提準面的概念,並確立準面到準線的研究路線,了各種傳動形式下準面與準線的具體特徵,證明了共軛準面上兩準線的誘導測地曲率等於零的這一不干涉條件,進而指,當準面為平行軸和相交軸傳動的節曲面時,不干涉條件自然滿足。
  6. The signal we named it fundamental wave ; according to the fundamental wave, coefficients of the fundamental wave can be lined in a sequence. when the unique of the dissolve of the fundamental wave can be confirmed, the sequence of the coefficients can be regarded as one of representation forms of the signal itself ; theory of dissolvable signal shows that when order of the matrix of fundamental wave sampling equals to number of fundamental waves, the sequence of the sampling values from sampling points must be matched one by one with the sequence of the coefficients of fundamental waves. the sampling composed by sequences of the sampling values must be full sampling ; the relevant deductions of the theory of dissolvable signal shows that when sampling the signal, sampling frequency must be lager than the ratio of the number of fundamental waves to the occupation time of the fundamental waves ; to band - limited signals, when the fundamental wave is a sine signal, the results from the relevant deductions of theory of dissolvable signal is coherent to the classic sampling theory

    本文通過分析認為,當信號集中的任一信號可表示為一系列已知信號的線性代數和時,信號集便構成可分解信號集,已知信號稱為基波信號;對可分解信號而言,基波系數構成一序列,當對指定的基波信號集分解唯一確定時,系數序列本身便是信號的一個表示;可分解信號采樣定當基波樣值矩陣的秩等於基波數時,則采樣點處的采樣樣構成的樣值序列必與基波系數序列一一對應,從而該樣值序列構成的采樣必為完全采樣;可分解信號采樣定中的推論指,對信號集進行采樣,采樣頻率必須大於其信號分解的基波數與其對應時長之比;對有限帶寬信號,若基波信號為正弦信號時,可分解信號采樣定推論的結論與經典采樣定一致。
  7. Scarcely had the first congratulations upon her marvellous escape been gone through when she wrote the following letter to madame danglars : - dear hermine, - i have just had a wonderful escape from the most imminent danger, and i owe my safety to the very count of monte cristo we were talking about yesterday, but whom i little expected to see to - day. i remember how unmercifully i laughed at what i considered your eulogistic and exaggerated praises of him ; but i have now ample cause to admit that your enthusiastic description of this wonderful man fell far short of his merits

    她一到家,在家人的一陣驚嘆平息之後,立刻寫了下面這封信騰格拉爾夫人: 「親愛的愛米娜:我剛才從九死一生的危險中奇跡般地逃了來,這全得歸功於我們昨天所談到的那位基督山伯爵但我決想不到今天會看見他我記得當你稱贊他的時候,我曾怎樣無情地加以嘲笑,覺得你的話太誇張了,可是現在我卻有充分的來相信:你對于這位奇人的描寫雖然熱情,但對於他的優點說的卻遠遠不夠。
  8. The paper will study the upper questions based on the two interconnection networks. first, we give a fault - tolerant routing algorithm under the connectivity of the crossed cube in o ( n ) time and the length of the longest routing path ; second, with the rapid progress in vlsi, the failing probability of processors and links is very low, the traditional connectivity underestimates the resilience of large networks / here by applying the concept " conditional connectivity " introduce by harary, we show that the n - crossed cube can tolerate up to 2n - 3 ( n > 2 ) processors failure and remain connected provide that all the neighbors of each processor do not ' fail at the same time, the result is the same as the hypercube. we also give a related algorithm in o ( n ) time, and the length of the longest path ; third, we apply cluster faun tolerance introduced by q. - p

    根據menger定, n -維交叉立方體可以容納n - 1個故障頂點,我們了它的時間復雜度為o ( n )的容錯路選擇演算法及其最長路徑長度分析;在此基礎上本文證明, n -維交叉立方體的條件連通度為2n - 2 ( n 2 ) ,並了相應時間復雜度為o ( n )的演算法及其最長路徑長度;除此之外,本文還證明當n -維交叉立方體中的故障簇個數不大於n - 1 ,其直徑不大於1 ,故障頂點總數不超過2n - 3 ( n 2 )時,交叉立方體中任兩個無故障頂點都至少有一條可靠路徑。
  9. The principle of piezoelectric modal sensor is introduced and the formulas of calculating modal respondence by measured piezoelectric outputs are gained

    介紹了壓電模態傳感器的實現原, ?實測壓電單元輸得到結構模態響應的計算公式。
  10. The boundary condition at bed surface of diffusion equation of nonuniform sediment is derived based on the concept of exchange intensity of stochastic theory by the author

    摘要文中首先我們建立的床面泥沙交換論導的非均勻沙擴散方程的邊界條件。
  11. Rock and roll music was first approved of by the us government because of its patriotic message during world war ii

    第三步:讓學生討論每條陳述,判斷它們是對是錯並給出理由
  12. Chelsea assistant manager steve clarke made no excuses for the blues defensive display

    切爾西的助教練史緹夫.克拉克沒有對藍軍的防禦戰術給出理由
  13. Note : when declining an invitation, an explanation or excuse should normally be given

    注意:當拒絕邀請時,一般要給出理由或解釋。
  14. Look at the pictures above. decide if they are junk food or healthy food. give reasons for your decisions

    看看上面的圖畫,確定它們是垃圾食品還是健康食品,並給出理由
  15. Topic : do you agree or disagree with the following statement ? aaa. use specific reasons and details to support your answer

    一個論點,主要是對兩個事物進行比較的陳述,要求考生支持或反對並給出理由
  16. Either user or cleverlearn may terminate your use of the cleverlearn software and services at any time, with or without cause, upon notice

    13 .服務終止用戶或cleverlearn可隨時在發通知的前提下終止使用cleverlearn服務,無需給出理由
  17. Topic : some people like a ; others like b. which one do you prefer - - a or b ? give specific reasons and examples to illustrate your answer

    兩個對立事物或一個事物對立的兩個方面,要求考生說明二者為什麼不同或比較它們的優缺點,並給出理由
  18. Topic : newspapers contain many information topics such as sports, current events, business and entertainment. which topic do you like to read most often ? give reasons, to explain your answer

    報紙包含了很多信息主題,比如:體育、時事、商業和娛樂等等。通常你喜歡讀哪個主題?給出理由解釋你的回答。
  19. Either user or cleverlearn may terminate your use of the cleverlearn software and services at any time, with or without cause, upon notice. any notice by you to cleverlearn concerning termination or cancellation shall be in accordance with any procedures that may be established by cleverlearn from time to time in its sole discretion

    服務終止用戶或慧學英語可隨時在發通知的前提下終止使用慧學英語服務,無需給出理由。你的終止或取消服務通知必須符合慧學英語制定的相關程序。
  20. 3. according to the spline theory we presented a shape matching algorithm based on the similarity matrix of curvature and torsion values of 3d curve, we reduced the 3 - d curve matching task into a 1 - d string matching problem, which makes the matching more veracious and can be used on the 2d or 3d curve matching. in order to reduce the cost of matching, we used multiple scale technique

    依據樣條曲線的基本論,研究了基於b樣條的輪廓曲線的匹配方法,輪廓曲線不變量曲率和撓率構造的相似不變量的選取以及基於相似矩陣的匹配演算法,並對該演算法的時間復雜度作了估計,同時,將多尺度技術引入到物體輪廓的匹配問題中。
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