modulo 中文意思是什麼
modulo
解釋
【數學】對…模。-
This paper analyses the coupling wastage in columniform wave guide gas laser, and gives the function between the coupling wastage of laser guide modulo eh11 and the position and radius of reflector
摘要分析了圓柱形波導氣體激光器中的耦合損耗，給出了最低階波導模eh11的耦合損耗與反射鏡位置、曲率半徑的函數關系。 -
We can try and solve congruences modulo pn for higher and higher value of n.
我們可以對越來越大的n去試解modpn的同余式。 -
However the time - consuming modulo exponentiation computation, which has always been the bottle - neck of rsa, restricts its wider application
但該演算法所採用的冪剩餘計算會耗費太多的時間，一直是制約其廣泛應用的瓶頸。 -
The last digit is an all important " fail safe " for accuracy of scanning. the check digit is derived by a modulo - 1o calculation from all the other digits in the number, via the following procedure
組成，代表商品之原產國家代號，系由ean指定為各會員國之條碼推廣機構的國家代表號。 -
Addition, subtraction, multiplication, division, and modulo
加法、減法、乘法、除法和取模。 -
Class to perform a modulo operation on the hash code returned by the
方法返回的哈希代碼執行求模操作。 -
We can try and solve congruences modulo pn for higher and higher value of n
我們可以對越來越大的n去試解mod pn的同余式。 -
Steganography using dual - modulo arithmetic without introducing histogram abnormality
採用兩次模運算的無直方圖異常安全密寫法 -
In a modulo check, the number by which the summed digits are divided
在模數檢驗法中，一個和數用某個數來除，其中的除數稱為模數。 -
The fmod ( ) function divides x by y and returns the remainder ( modulo ) of the division
函數的作用是：返回通過除法求得的浮點數余數。 -
Reduces the total seconds modulo 86, 400, which is the number of seconds in a day
從總秒數中減去86 ， 400的最大整數倍數。 86 ， 400是一天的秒數。 -
To ensure normalized values inches 12. 0, the constructor performs modulo 12 arithmetic
為了確保使用標準形式的值（英寸< 12 . 0 ） ，構造函數執行對12的求模運算。 -
Generally, this problem is reduced to quadratic residue problem of modulo a big prime number
一般而言，該問題歸結為模大素數的二次剩餘問題，但這種歸結不能用於最優擴域oef 。 -
In addition to standard addition, subtraction, multiplication, and division, awk allows us to use the previously demonstrated exponent operator " ", the modulo remainder operator " % ", and a bunch of other handy assignment operators borrowed from c
除了標準的加、減、乘、除， awk還允許使用前面演示過的指數運算符" ^ " 、模（余數）運算符" % "和其它許多從c語言中借入的易於使用的賦值操作符。 -
In the key generation algorithm, a best method of generating key is found through theory analysis and many experiments. in the multiplicative inverse of modulo, a new algorithm is initiated which needs less memory and runs faster than extended euclid
對于求模逆元演算法，在擴展歐拉演算法的基礎上，提出了一種新的求模逆元演算法，該演算法比擴展歐拉演算法不僅內存所需更少，而且運行速度更快。 -
Furthermore, the scheme is improved, and it is shown that the improved scheme is more secure than the original by analyzing the security of the improved scheme, and has only one exponentiation modulo p and two hash - function evaluations for verification
此外，對原方案進行了改進，通過對改進方案的安全性分析得出結論；改進方案此原方案更安全，並且消息恢復過程只需要計算一次大數模冪乘和兩次單向函數。 -
The principal purpose of this paper is to consider the bounds of solutions of the cubic equation with the prime variables in arithmetic progressions modulo k > 1
本文的主要目的是估計三次素變數方程的解在模k 1算術數列中的上界。 -
This book is composed of following sections : in the first section, we present the nessary definitions and give a well - rounded treatment of known families of almost difference sets ; in the second section, we discuss the possibility of constructing almost difference sets with 2, 4 and 6 order cyclotomy classes ; in the third section, we construct two new families of almost difference sets by using cyclotomy modulo pq, where p and q are distinct primes ; in the last section, we discuss the methord to construct almost difference sets with difference sets
然而即使這樣，已發現的幾乎差集還是很有限。本文由以下四個部分組成：第一部分給出必要的定義和綜述；第二部分就2階、 4階及6階分圓類可能構成幾乎差集的情形給于討論；第三部分利用模pq （ p ， q為互異素數）分圓類構造了兩類新的幾乎差集；第四部分討論了由差集構造幾乎差集的方法。 -
In the implementation of tpm, two algorithms are improved. one is key generation. the other is multiplicative inverse of modulo
其中，重點改進了可信平臺模塊所用的兩個演算法:密鑰生成演算法和求模擬元演算法。 -
For these conversions, precision is always truncated never rounded and overflow is handled as modulo of the destination type, which is smaller. for example, calling
對于這些轉換，總是直接截取有效位數（從不四捨五入） ，而溢出則按目標類型取模處理，以較小者為準。
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