junnila 中文意思是什麼
junnila
解釋
雲尼拉-
In 1986, in the paper [ 1 ] junnila proved the result : a space is hereditarily metacompact iff its every scattered partion has a point finite open expansion. and in the paper [ 2 ], by the example 3. 2 zhu peiyong proved that the hereditarily paracompact spaces have no a similar characterization to junnila ' s
Junnila在文[ 1 ]中證明了：一個空間是遺傳亞緊的當且僅當它的每個散射分解有一個點有限的開膨脹。而朱培勇在文[ 2 ]中用例3 . 2從反面證明了：遺傳仿緊空間不與空間的每個散射分解有局部有限的開膨脹等價。 -
The paper has four parts. the first chapter, introduction, gives the origin of the problems and our main results. the second chapter proves that countable paracompact ( mesocompact, metacompact ) spaces have the characterization of junnila ' s and that hereditarily mesocompact spaces do n ' t have it. at last, we give the sufficient conditions for a space having the property that its every scattered partition has a compact - finite open expansion
第二章詳細證明了可數仿緊（中緊、亞緊）空間有類似junnila的刻畫，遺傳中緊空間不具有類似junnila的刻畫，最後給出了正則空間的每個散射分解有緊有限的開膨脹的充要條。
分享友人